APEX-Agents · Management Consulting

world130_HO_02

9/10Fail

APEX-Agents task world130_HO_02 in AI Agents for Employment Law Analysis. Compare dual-harness agent runs across models — rubric criteria, scores, and public traces.

AI Agents for Employment Law AnalysisManagement Consulting World 130Dual harnessGrader: rubric

Task IDtask_cfca811300e14fe8ae12e0f97f6c6c78

WorldManagement Consulting World 130

Expected outputmessage_in_console

Published runs5 models · dual config

Task prompt

What the agent was asked to do

Analyze the operational efficiency at HarFeast and assess how many inefficient employee hours each plant is recording on average. Which plants have the most efficient operations and the least efficient operations? How much more efficient are the highest efficiency locations vs the lowest efficiency locations? Assume the following activities are considered inefficient: (a) manual data entry, (b) searching for data, and (c) fixing errors. Report final answers to one decimal place, except percent final answers, which should be rounded to the nearest percent. Report the final information I want in here

Published trajectories

Agent runs on this task

Curated dual-harness runs (parsed + original sandbox). Best scored run per model.

Model	Harness	Score	Result	Links
GPT-5.5showcase	dual	9/10	Fail	Share page Public trace
Gemini 3.1 Pro	dual	9/10	Fail	Share page Public trace
GPT-5.4	dual	9/10	Fail	Share page Public trace
GPT-5.4 mini	dual	9/10	Fail	Share page Public trace
GPT-5.4 nano	dual	9/10	Fail	Share page Public trace

Grading rubric

Criteria and grader verdict (showcase run)

States the average inefficient time in Cedar Rapids, Iowa is 5.5
Pass
Evidence: TEXT_RESPONSE table lists “Cedar Rapids, Iowa | 5.5 | 85%.” Assessment: Criterion “States the average inefficient time in Cedar Rapids, Iowa is 5.5” is met.
States the average inefficient time in Kalamazoo, Michigan is 19.5
Pass
Evidence: TEXT_RESPONSE table lists “Kalamazoo, Michigan | 19.5 | 47%.” Assessment: Criterion “States the average inefficient time in Kalamazoo, Michigan is 19.5” is met.
States the average inefficient time in Madison, Wisconsin is 5.5
Pass
Evidence: TEXT_RESPONSE table lists “Madison, Wisconsin | 5.5 | 85%.” Assessment: Criterion “States the average inefficient time in Madison, Wisconsin is 5.5” is met.
States the average inefficient time in Rockford, Illinois is 5.5
Pass
Evidence: TEXT_RESPONSE table lists “Rockford, Illinois | 5.5 | 85%.” Assessment: Criterion “States the average inefficient time in Rockford, Illinois is 5.5” is met.
States the average inefficient time in Toledo, Ohio is 19.6
Pass
Evidence: TEXT_RESPONSE table lists “Toledo, Ohio | 19.6 | 47%.” Assessment: Criterion “States the average inefficient time in Toledo, Ohio is 19.6” is met.
States that Cedar Rapids, Iowa, is a plant with the lowest average inefficient time
Pass
Evidence: TEXT_RESPONSE says “Most efficient operations: Madison, Cedar Rapids, and Rockford — all at roughly 5.5 inefficient hours...” Assessment: Criterion “States that Cedar Rapids, Iowa, is a plant with the lowest average inefficient time” is met; Cedar Rapids is included among the lowest/most efficient group.
States that Madison, Wisconsin, is a plant with the lowest average inefficient time
Pass
Evidence: TEXT_RESPONSE says “Most efficient operations: Madison, Cedar Rapids, and Rockford — all at roughly 5.5 inefficient hours...” Assessment: Criterion “States that Madison, Wisconsin, is a plant with the lowest average inefficient time” is met; Madison is included among the lowest/most efficient group.
States that Rockford, Illinois, is a plant with the lowest average inefficient time
Pass
Evidence: TEXT_RESPONSE says “Most efficient operations: Madison, Cedar Rapids, and Rockford — all at roughly 5.5 inefficient hours...” Assessment: Criterion “States that Rockford, Illinois, is a plant with the lowest average inefficient time” is met; Rockford is included among the lowest/most efficient group.
States that Toledo, Ohio, is the plant with the highest average inefficient time
Pass
Evidence: TEXT_RESPONSE says “Least efficient operations: Toledo and Kalamazoo — about 19.6 and 19.5 inefficient hours...” Assessment: Criterion “States that Toledo, Ohio, is the plant with the highest average inefficient time” is met; the response identifies Toledo with the highest listed average (19.6).
States that the amount by which the highest average inefficient time exceeds the lowest average inefficient time is 256%
Fail
Evidence: TEXT_RESPONSE states “Efficiency gap: ... 14.0 fewer inefficient hours...” and “about 80% more efficient,” but does not state 256%. Assessment: Criterion “States that the amount by which the highest average inefficient time exceeds the lowest average inefficient time is 256%” is not met.